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2208                                                       软件学报  2025  年第  36  卷第  5  期


                        序号  18  19  20  21  22  23  24  25  26  27   28  29  30  31  32  33  34   35





                        s = (1+d) −1 (k +r)−r  d 1 d 2 +d 1 d 2 k 2 +k 1 +(d 1 d 2 −1)r  2  ) +d 1 d 2 +(d 1 d 2 −1)r  d 1 d 2 +d 1 d 2 k 2 +k 1 +(d 1 d 2 −1)r  d 1 +d 1 d 2 k 2 +k 1 +(d 1 d 2 −1)r  d 1 d 2 k 2 +d 1 +d 2 k 1 +(d 1 d 2 −1)r  1  d 1 d 2 k 2 +d 1 +d 2 k 1 +(d 1 d 2 −1)r  1  d 1 k 2 +d 1 +d 2 k 1 +(d 1 d 2 −1)r  1 d 1 d 2 +d 1 d 2 k 2 +d 1 +d 2 k 1 +(d 1 d 2 −1)r  1 d 1 d 2 +d 1 k 2 +d 1 +d 2 k 1 +(d 1 d 2 −1)r  1 d 1 d 2 +d 1 d 2 k 2 +d 1 +d 2 k 1 +(d 1 d 2







                              ( k 2 +d −1 k 1  1  2  2   2                    2       2
                                d 1
                                                                 2                            2


                                                       )   )   )    )               )       )
                          )   )   )    )   )   )   )     1   1   1    1  )  )           )        )
                    (续)     2                1   1   1                          )
                        1                                                             2
                        2 +w ′                           2
                    表 A1    基于乘法密钥拆分的两随机数框架的实例化
                        k = d 1 w ′  (1+d) ( d 1 d 2 +k 1 +d 1 d 2 k 2  (1+d) ( d 1 d 2 +d 1 k 2 +k 1  (1+d) ( d 1 d 2 +d 1 d 2 k 2 +k 1  2  (1+d) ( d 1 +d 1 d 2 k 2 +k 1  (1+d) ( d 1 d 2 k 2 +d 1 +d 2 k 1  (1+d) ( d 1 d 2 k 2 +d 1 +d 2 k 1  2  (1+d) ( d 1 k 2 +d 1 +d 2 k 1  (1+d) ( d 1 d 2 +d 1 d 2 k 2 +d 1 +d 2 k 1  (1+d) ( d 1 d 2 +d 1 k 2 +d 1 +d 2 k 1  (1+d) ( d 1 d 2 +d 1 d 2 k 2 +d 1 +d 2 k 1  (1+d) ( d 1 +d 1 d 2 k 2 +d 1 +d 2 k 1  (1+d) ( d 1 d 2 k 2 +d 1 +k 1  (

                                                                 2


                                                                                          2


                              )
                        k = w 2 +d −1 w 1  2  1+d 2 k 2 +d −1 d −1 k 1  2  1  1+d −1 ( k 2 +d −1 k 1  1  d 2 +k 2 +d −1 d −1 k 1  2  1  d −1 +k 2 +d −1 d −1 k 1  2  1  k 2 +d −1 +d 1 d −1 k 1  2  2  d 2 k 2 +d −1 +d 1 d −1 k 1  2  2  d −1 k 2 +d −1 +d 1 d −1 k 1  2  2  1+d 2 k 2 +d −1 +d 1 d −1 k 1  2  2  1+d −1 k 2 +d −1 +d 1 d −1 k 1  2  2  d 2 +k 2 +d −1 +d 1 d −1 k 1  2  2  d −1 +k 2 +d −1 +d 1 d −1 k 1  2  2  k 2 +d −1 +d −1 d −1 k 1  2  1  2  d 2 k 2 +d −1 +d −1 d −




                                2        2                   2                            2
                                                     2                            2
                                                                      2
                                                                                                  2




                          )  2    )                    )  2    )                    )  2    )
                            (1+d) ( d 2 +d 2 k 2  (1+d) ( d 2 +d 2 k 2  (1+d) ( d 2 +d 2 k 2  (1+d) ( d 2 +d 2 k 2  (1+d) ( d 2 +d 2 k 2  (1+d) ( d 2 +d 2 k 2
                        w ′  2  (1+d)(d 2 +k 2 )  2  (1+d)(1+d 2 k 2 )  (1+d)d 2 k 2  (1+d)d 2 k 2  2  (1+d)k 2  (1+d)(d 2 +k 2 )  2  (1+d)(1+d 2 k 2 )  (1+d)d 2 k 2  (1+d)d 2 k 2  2  (1+d)k 2  (1+d)(d 2 +k 2 )  2  (1+d)(1+d 2 k 2 )


                                                       )  1
                        w ′  1                           (1+d) ( d 1 +d 2 k 1         (1+d)(d 1 +k 1 )



                       w 2  1+d 2 k 2  1+d −1 k 2  2  d 2 +k 2  d −1 +k 2  k 2  d 2 k 2  d −1 k 2  1+d 2 k 2  1+d −1 k 2  2  d 2 +k 2  d −1 +k 2  k 2  d 2 k 2  d −1 k 2  1+d 2 k 2  1+d −1 k 2  2  d 2 +k 2  d −1 +k 2
                                         2           2                2           2               2


                       w 1                              1+d 1 k 1                     1+d −1 k 1  1
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